Topic
Quick answer A long-running MCP tool that gives no feedback turns the agent into a black box. The agent cannot tell whether the tool is working, has stalled, or should
Read articleQuick answer When an agent resolves a merge conflict, do not trust a cleanly completed merge. The default behavior of most coding agents is to make the conflict disappear, not
Read articleAsked to reconcile a list, the agent wrote a per-item loop over a single endpoint. Three-row fixtures looked fast; staging fired hundreds of calls and throttled, even though a bulk endpoint already existed. Check for a batch path before writing the loop.
Read articleQuick answer: An MCP tool is a piece of code that can read and act on real data, so it deserves the same security review as any service you deploy.
Read articleQuick answer: If your agent has a working MCP tool for an API but the model still hand-writes a fetch, the failure is usually one of three things: the tool&
Read articleQuick answer: An MCP tool should return a structured, machine-readable error when something goes wrong, not let a raw exception bubble up. The agent calling the tool has to decide
Read articleQuick answer: When an agent adds a "small helper" that already exists elsewhere in the repo, you don't just have a duplicate file. You now have
Read articleQuick answer: When an MCP server runs through a hosted registry, the operator's view of what the server actually did is limited to whatever logs and metrics the
Read articleQuick answer: An AI coding assistant like Cursor will happily generate a request that looks correct in the editor but drifts from the actual API contract, because it is working
Read articleQuick answer: When an MCP tool returns a large result set in one response, the practical limit is not abstract; transport frames, model context windows, and client memory all cap
Read articleQuick answer: When an agent fixes a bug at the call site where the error surfaced, it usually closes that one ticket and leaves the identical defect in the other
Read articleA timeout does not prove the server failed. The agent added an automatic retry to a POST on timeout, and the first request had already committed, so the second created a duplicate. Retry logic belongs on idempotent calls, or it needs an idempotency key.
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